Y=-0.06x^2+0.96x

Solution for Y=-0.06x^2+0.96x equation:

=-0.06Y^2+0.96Y

We move all terms to the left:

-(-0.06Y^2+0.96Y)=0

We get rid of parentheses

0.06Y^2-0.96Y=0

a = 0.06; b = -0.96; c = 0;
Δ = b2-4ac
Δ = -0.962-4·0.06·0
Δ = 0.9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.96)-\sqrt{0.9216}}{2*0.06}=\frac{0.96-\sqrt{0.9216}}{0.12}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.96)+\sqrt{0.9216}}{2*0.06}=\frac{0.96+\sqrt{0.9216}}{0.12}
$